Intel® Software Network

The following program is fine when compiled (on Windows) with
ifort err.f90
but when compiled with the fp stack checking option
ifort /Qfp-stack-check err.f90
it gives access violation when executed.

In my debugging efforts I've been turning on all the stack checking options, but this one seems to create a bug itself. 
Interestingly, commenting out either of the two executable statements in subroutine zzz makes it OK.
Any comments Steve?

cheers
Gib

! err.f90
module errmod
implicit none
contains
subroutine zzz(m)
integer :: m(3)
integer :: n(3)
real :: x(3)

x = m
n = x

end subroutine
end module

program err
use errmod
integer :: site(3) = (/1,2,3/)
call zzz(site)
end

The option is /Qfpstkchk

I tried your code both from the command line and within VS without a problem
(VS2005 and IVF 9.1.028)

Les

Access violation is exactly what to expect when the FP stack check option finds a problem.

I can reproduce the error - let me investigate.

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Steve

Doctor Fortran: intel.com/software/drfortran

By the way, the correct spelling of the option in version 10.1 is /Qfp-stack-check.  The older spelling /Qfpstkchk has been deprecated. I don't see the error with 9.1 nor with the internal build of our next major release (still a ways away).

As best as I can tell, this is a compiler bug.  It occurs only with optimization level 2 or 3.  I have reported this to development.  If you report the issue to Intel Support, please reference T85092-CP.

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Steve

Doctor Fortran: intel.com/software/drfortran

Thanks Steve.

The problem you encountered was reported earlier and is fixed in our next major release.  A workaround is to use /QxN or whatever other appropriate version of /Qx is that would generate SSE code instead of x87 (no FP stack, runs faster.) Reference: T80134-CP.

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Steve

Doctor Fortran: intel.com/software/drfortran